1.

On constructing a triangle ABC, with AB = 4.3 cm, AC = BC = 5.6 cm, the distance between the points which are both equidistant from AB and AC and also 1 cm from BC is

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On constructing a triangle ABC, with AB = 4.3 cm, AC = BC = 5.6 cm, the distance between the points which are both equidistant from AB and AC and also 1 cm from BC is




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