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On constructing a triangle ABC, with AB = 5.6 cm, AC = BC = 9.2 cm, the distance between the points which are both equidistant from AB and AC and also 2 cm from BC is |
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Answer» On constructing a triangle ABC, with AB = 5.6 cm, AC = BC = 9.2 cm, the distance between the points which are both equidistant from AB and AC and also 2 cm from BC is |
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