1.

On constructing a triangle ABC, with AB = 5 cm, AC = BC = 9 cm, the distance between the points which are both equidistant from AB and AC and also 3 cm from BC is

Answer»

On constructing a triangle ABC, with AB = 5 cm, AC = BC = 9 cm, the distance between the points which are both equidistant from AB and AC and also 3 cm from BC is




Discussion

No Comment Found

Related InterviewSolutions