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On constructing a triangle ABC, with AB = 5 cm, AC = BC = 9 cm, the distance between the points which are both equidistant from AB and AC and also 3 cm from BC is |
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Answer» On constructing a triangle ABC, with AB = 5 cm, AC = BC = 9 cm, the distance between the points which are both equidistant from AB and AC and also 3 cm from BC is |
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