1.

On dissolving 2.34g of non-electrolyte solute in 40g of benzene, the boilingpoint of solution was higher than benzene by 0.81K. Kb value for benzene is 2.53 K kgmol^(-1) .Calculate the molar mass of solute. [Molar mass of benzene is78 gmol^(-1)]

Answer»

Solution :(a)Data: Mass of solute = `W_(2)` = 2.34 g,
`K_(B) = 2.53 K.kg mol^(-1)`,
Molar mass of solute = `M_(2)`= ?
Mass of solvent benzene = WJ = 40 g
Elevation in boiling point =0.81 K
Formula: `M2=W_(2)/W_(1) 1000`
Substituion: `M_(O_(2))=2.53xx2.34xx(1000)/(40)xx1/0.81`
Answer: `M_(2) = 182.72 g mol^(-1)`
(b) (II) Solubility of gas decreases with increase in temperature and INCREASES with increase in pressure.


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