1.

On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

Answer»

10



Clearly, (2272 - 875) = 1397, is exactly DIVISIBLE by N.

Now. 1397 = 11 * 127

The REQUIRED 3-DIGIT number is 127, the sum of whose digit is 10.



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