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On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is: |
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Answer» Clearly, (2272 - 875) = 1397, is exactly DIVISIBLE by N. Now. 1397 = 11 * 127 The REQUIRED 3-DIGIT number is 127, the sum of whose digit is 10. |
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