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On dividing `x^3-3x^2+x+2`by a polynomial the quotient and remainder were `x-2`and `-2x+4`, respectively. Find g(x). |
Answer» Divident=`(x^3-3x^2+x+2)` Quotient=(x-2) Remainder=(-2x+9) Divisor=g(x) =Divident=Divisor*quotient+remainder =`(x^3-3x^2+x+2)=g(x)*(x-2)+(-2x+4)` after solving this equation g(x)=`x^2-x+1` |
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