1.

On dividing `x^3-3x^2+x+2`by a polynomial the quotient and remainder were `x-2`and `-2x+4`, respectively. Find g(x).

Answer» Divident=`(x^3-3x^2+x+2)`
Quotient=(x-2)
Remainder=(-2x+9)
Divisor=g(x)
=Divident=Divisor*quotient+remainder
=`(x^3-3x^2+x+2)=g(x)*(x-2)+(-2x+4)`
after solving this equation
g(x)=`x^2-x+1`


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