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On electrolysis of a solution of dilute `H_(2)SO_(4)` between platinum electrodes , the gas evolved at the anoe isA. `SO_(2)`B. `SO_(3)`C. `O_(2)`D. `H_(2)` |
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Answer» Correct Answer - c Oxidation potential of `H_(2)Ogt` Oxidation potential of `SO_(4)^(2-)` So oxidation of `H_(2)O` occurs at anode and gives `O_(2)(g)`. |
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