On gram of the carbonate of a metal was dissolve din 35 CC 1N HCl.The resulting liquid required 50 CC N/10 caustic soda solution to neutralise it completely. The equivalent weight of metal carbonate is

On gram of the carbonate of a metal was dissolve din 35 CC 1N HCl.The

1.	On gram of the carbonate of a metal was dissolve din 35 CC 1N HCl.The resulting liquid required 50 CC N/10 caustic soda solution to neutralise it completely. The equivalent weight of metal carbonate is
Answer» 100 25 53 50 Solution :`"50CC of "(N)/(10)NAOH="50CC of "(N)/(10)HCl` `=5C C 1NHCl` Volume of ACID left = `5C C 1NHCl` Volume of acid used by metal carbonate = `25.5 = 20C C 1 NHCl` No. of MeQ of `HCl=20xx1=20` No. of meQ of metal carbonate = `(1)/("GEW of M.C")xxoverset("1")(1000)` No. of mecq of HCl = No. of mecq of metal carbonate `20=(1)/("GSW of M.C.")XX100` GTW of M.C = 50 `therefore` EQ wt of M.C. = 50