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On heating 0.2g of an organic compound with a mixture of barium chloride and nitric acid, 0.466 g of barium sulphate was obtained. Calculate the percentage of sulphur |
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Answer» Solution :WEIGHT of substance = w = 0.2g , weight of barium SULPHATE `= w_(4) = 0.466g` weight PERCENTAGE of sulphur = `(w_(4)XX32XX100)/(wxx233) =(0.466xx32xx100)/(0.2xx233) = 32%` |
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