1.

On heating 0.2g of an organic compound with a mixture of barium chloride and nitric acid, 0.466 g of barium sulphate was obtained. Calculate the percentage of sulphur

Answer»

Solution :WEIGHT of substance = w = 0.2g , weight of barium SULPHATE `= w_(4) = 0.466g`
weight PERCENTAGE of sulphur = `(w_(4)XX32XX100)/(wxx233) =(0.466xx32xx100)/(0.2xx233) = 32%`


Discussion

No Comment Found