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On heating 0.32g of an organic compound with concentrated nitric acid and barium chloride, 0.932g barium sulphate was obtained. Calculate the percentage of sulphur in the given compound. |
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Answer» Solution :Mass of organic compound, `W = 0.32g` Mass of barium sulphate, `W_(1) = 0.932g` `underset(233g)(BaSO_(4))-= underset(32g)(S)` Percentage of sulphur `= (32)/(233) XX (W_(1))/(W) xx 100` `= (32)/(233) xx (0.932)/(0.32) xx 100 = 40%` |
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