1.

On heating 0.32g of an organic compound with concentrated nitric acid and barium chloride, 0.932g barium sulphate was obtained. Calculate the percentage of sulphur in the given compound.

Answer»

Solution :Mass of organic compound, `W = 0.32g`
Mass of barium sulphate, `W_(1) = 0.932g`
`underset(233g)(BaSO_(4))-= underset(32g)(S)`
Percentage of sulphur `= (32)/(233) XX (W_(1))/(W) xx 100`
`= (32)/(233) xx (0.932)/(0.32) xx 100 = 40%`


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