On heating, lead (II) nitrate gives a brown gas 'A'. The gas 'A' on cooling changes to colocurless solid 'B'. Solid 'B' on heating with NO changes to a blue solid 'C'. Identify 'A', 'B' and 'C' and also write reactions involved and draw the structures of 'B' and 'C'.

On heating, lead (II) nitrate gives a brown gas 'A'. The gas 'A' on co

1.	On heating, lead (II) nitrate gives a brown gas 'A'. The gas 'A' on cooling changes to colocurless solid 'B'. Solid 'B' on heating with NO changes to a blue solid 'C'. Identify 'A', 'B' and 'C' and also write reactions involved and draw the structures of 'B' and 'C'.
Answer» Solution :(i) Since LEAD (II) nitrate on heating GIVES a brown gas 'A' therefore, gas 'A' MUST be nitrogen DIOXIDE `(NO_(2))`. `{:underset("Lead (II) nitrate")(2Pb(NO_(3))_(2))overset(Delta,673K)to2PbO+underset("Brown gas (A)")(4NO_(2))+O_(2):}` (ii) The brown gas 'A' on cooling dimerises to give a colourless SOLID 'B' therefore 'B' must be `N_(2)O_(4)` (dinitrogen tetroxide). `{:2NO_(2)underset("On heating")overset("On cooling")hArrunderset("Colourless solid (B)")(N_(2)O_(4))` (iii) Since colourles solid 'B' on heating with NO, gives a blue solid 'C' therefore 'C' must be dinitrogen trioxide. `{:2NO+underset("Colourless solid (B)")(N_(2)O_(4))tounderset("Blue solid (C))(2N_(2)O_(3)):}` Thus, `A=NO_(2),B=N_(2)O_(4)andC=N_(2)O_(3)`. For structures,