On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of `CuCl_(2)` , all copper of the solution of `CuCl_(2)` solution was (Molar mass of Cu = 63.5 , Faraday constant = `96500 C mol^(-1)`).A. 0.07 MB. 0.2 MC. 0.005 MD. 0.02 M

On passing a current of 1.0 ampere for 16 min and 5 sec through one li

1.	On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of `CuCl_(2)` , all copper of the solution of `CuCl_(2)` solution was (Molar mass of Cu = 63.5 , Faraday constant = `96500 C mol^(-1)`).A. 0.07 MB. 0.2 MC. 0.005 MD. 0.02 M
Answer» Correct Answer - C `Q = 1 xx 965 = 965` C `Cu^(2+) + 2e^(-) to Cu`, `2 xx 96500` C decompose `CuCl_(2) = 1 ` mole `therefore` 965 C decompose `CuCl_(2) = (1 xx 965)/(2 xx 96500) =(1)/(200)` mole This was present in one litre of `CuCl_(2)` solution . Hence , strength = 0.005 M.

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On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of `CuCl_(2)` , all copper of the solution of `CuCl_(2)` solution was (Molar mass of Cu = 63.5 , Faraday constant = `96500 C mol^(-1)`).A. 0.07 MB. 0.2 MC. 0.005 MD. 0.02 M

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