1.

on passing a current of 1.0 ampre for 16 min and 5 sec through one litre solution of CuCl_(2) all the copper of the solution was solution was peposited at cathode. The strength of CuCl_(2) solution was (Molar mass of Cu=63.5 faraday constant =96500 C mol^(-1))

Answer»

0.07 M
0.2 N
0.005 N
0.02 N

Solution :`Q=IxxT`
`=1Axx965s=965 C`
`Cu^(2+)+UNDERSET(2xx96500 C)(2e^(-))to underset(1 "MOL")(Cu)`
`2 xx 96500 C `deposit COPPER = 1 mol
965 C deposite copper `=5xx10^(-3)` mol
`therefore` One litre of `CuCl_(2)` solution CONTAIN `=5xx10^(-3)` mol of solute
`therefore` Molarity of solution =0.005 M


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