On passingle C ampere of electricity through a electrolyte solution for t second, m gram metal deposits on cathode. The equivalent weight E of the metal isA. `E=(Cxxt)/(mxx96500)`B. `E=(Cxxm)/(txx96500)`C. `E=(96500xxm)/(Cxxt)`D. `E=(Cxxtxx96500)/(m)`

On passingle C ampere of electricity through a electrolyte solution fo

1.	On passingle C ampere of electricity through a electrolyte solution for t second, m gram metal deposits on cathode. The equivalent weight E of the metal isA. `E=(Cxxt)/(mxx96500)`B. `E=(Cxxm)/(txx96500)`C. `E=(96500xxm)/(Cxxt)`D. `E=(Cxxtxx96500)/(m)`
Answer» Correct Answer - C

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Based on the data given below, the correct order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt A1`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al^(-) lt Br^(-) lt Fe^(2+)`D. `Al^(-) lt Fe^(2+) lt Br^(-)`
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Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

On passingle C ampere of electricity through a electrolyte solution for t second, m gram metal deposits on cathode. The equivalent weight E of the metal isA. `E=(Cxxt)/(mxx96500)`B. `E=(Cxxm)/(txx96500)`C. `E=(96500xxm)/(Cxxt)`D. `E=(Cxxtxx96500)/(m)`

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