InterviewSolution
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InterviewSolution
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On radiation (sending out) an AM modulated signal, the total radiated power is due to energy carried by `omega_c, omega_c - omega_m and omega_c + omega_m`. Suggest ways to minimise cost of radiation without compromising on information. |
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Answer» In amplitude signal, only side band frequencies contain information. Thus only `(omega_(c ) + omega_(m))`and `(omega_(c )-omega_(m))` contain information. Now, according to question, the total radiated power is due to energy carried by `omega_(c), (omega_(c)-omega_(m))` and `(omega_(c)+omega_(m))`. Thus to minimise the cost of radiation without compromising on information `omega_(c)` can be left and transmitting. `(omega_(c ) + omega_(m)), (omega_(c )-omega_(m))` or both `(omega_(c ) + omega_(m))` and `(omega_(c )-omega_(m))`. |
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