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On reaction with Cl_(2), phosphorus forms two types of halides 'A' and 'B'. Halide A is yellowish-white powder but halide 'B' is colourless oily liquied. Identify A and B write the formulas of their hydrolysis products. |
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Answer» Solution :Since `Cl_(2)` REACTS with phosphours to form two halids (A and B), therefore, thses halides must be `PCl_(3)andPCl_(3)`. Since halide 'A' is a yellowish-white solid but halide 'B' is a colourless oily liquid, therefore, due to HIGHER molecular MASS and HENCE stronger forces of ATTRACTION, halide 'A' must be a solid, i.e., `PCl_(5)` and `P_(4)+10Cl_(2)to4PCl_(3)` (yellowish-white solid) `P_(4)+6Cl_(2)tounderset((B))(4PCl_(3))` (colourless oily liquid) halide 'B' must be a liquid i.e., `PCl_(3)`. Their hydrolysis products are shown below : `underset("Phosphorus pentachloride")(PCl_(5))+4H_(2)Otounderset("Orthophosphoric acid")(H_(3)PO_(4))+5HCl` `underset("Phosphorus trichloride")(PCl_(3))+3H_(2)Otounderset("Phosphorus acid")(H_(3)PO_(3))+3HCl` |
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