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On reduction with hydrogen , 3.6 g of an oxide of metal left 3.2 g of metal . If the simplest atomic weight of metal is 64, the simplest formula of the oxide isA. MOB. `M_(2)O_(3)`C. `M_(2)O`D. `M_(2)O_(5)` |
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Answer» Correct Answer - 3 `E=(3.2)/(0.4)xx8=64,mol.wt.=2xx32=64` `n=(64)/(64)=1` `therefore "Formula of metal oxide" = M_(2)O` |
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