On taking 60 g CH_(3)COOH and 46g CH_(3)CH_(2)OH in a 5 lit. lask in tle presence of H_(3)O^(+) (catalyst), at 298K 44 g of CH_(3)COOC_(2)H_(5) is formed at equilibrium. If amount of CH_(3)COOH is doubled without affecting amount of CH_(3)CH_(2)OH then, CH_(3)"COOC"_(2)H_(5) formed is

On taking 60 g CH_(3)COOH and 46g CH_(3)CH_(2)OH in a 5 lit. lask in t

1.	On taking 60 g CH_(3)COOH and 46g CH_(3)CH_(2)OH in a 5 lit. lask in tle presence of H_(3)O^(+) (catalyst), at 298K 44 g of CH_(3)COOC_(2)H_(5) is formed at equilibrium. If amount of CH_(3)COOH is doubled without affecting amount of CH_(3)CH_(2)OH then, CH_(3)"COOC"_(2)H_(5) formed is
Answer» 20.33 g 22 g 44 g 58.66g Solution :Case-I `CH_(3)COOH=(60)/(60)=1` MOL `CH_(3)CH_(2)OH=(46)/(46)=1` mol `CH_(3)COOC_(2)H_(5)=(44)/(88)=0.5` mol Case-II `CH_(3)COOH=2 mol, C_(2)H_(5)OH=1` mol `CH_(3)COOO_(2)H_(5)` =? `K_(c)` is not affected at temperature is constant `(x^(2))/(1-x^(2))=(y^(2))/((2-y)(1-y)), (y^(2))/((2-y)(1-y))=1` `y^(2)=(2-4)(1-4)=y^(2)-3y` `y=(2)/(3)` mole of ester = `(2)/(3) xx 58 = 58.66` g