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InterviewSolution
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On the 6 faces of a dice, the numbers 0, 1, 1, 1, 6, 6 are marked. Such these both dice are thrown at a time and the sum of the digits on the top faces is noted.(i) How many total number of possible outcomes.(ii) What is the probability of getting a sum of 7 on the top faces. |
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Answer» Two dices contain the numbers 0, 1, 1, 1, 6, 6 on the faces each. The all possible outcomes will be: (0, 0), (0, 1), (0, 1), (0, 1), (0, 6), (0, 6) (1, 0), (1, 1), (1, 1), (1, 1), (1, 6), (1, 6) (1, 0), (1, 1), (1, 1), (1, 1), (1, 6), (1, 6) (1,0), (1, 1), (1, 1), (1, 1), (1, 6), (1, 6) (6, 0), (6, 1), (6, 1), (6, 1), (6, 6), (6, 6) (6, 0), (6, 1), (6, 1), (6, 1), (6, 6), (6, 6) (i) The possible numbers which have different outcomes are (0, 0), (0, 1), (0, 6), (1, 0), (1, 1), (1, 6), (6, 6) Hence, the possible outcomes are : (0, 1, 2, 6, 7, 12) (ii) Total number of all possible outcomes = 36 The numbers that have a sum 7 are (1,6), (1,6), (1,6), (1,6), (1,6), (1,6) (6, 1), (6, 1), (6, 1), (6, 1), (6, 1), (6, 1) The number of favourable outcomes = 12 ∴ The probability of getting a sum of 7 = \(\frac { 12 }{ 36 }\) = \(\frac { 1 }{ 3 }\) |
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