1.

On the basis of the following E^(@) values the stongest oxidizing agent is [Fe(CN_(6)]^(4-)rarr[Fe(CN)_(6)]^(3-)+E^(-1),E^(@)=-0.35 v Fe^(2+)rarrFe^(3+)+E^(-1),E^(@)=-0.35 v

Answer»

`Fe^(3+)`
`[Fe(CN)_(6)]^(3-)`
`[Fe(CN)_(6)^(4-)]`
`Fe^(2+)`

Solution :`[Fe(CN)_(6)]^(3)+E^(-)rarr[Fe(CN)_(6)]^(4)`
`E^(2)+=0.35V`
`Fe^(3+)+E^(-)rarrFe^(2+), E^(@)=+0.77` V
higher +ve electrode POTENTIAL STRONGER is the oxidising agent thus OPTION (a) is CORRECT


Discussion

No Comment Found