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On the basis of the following `E^(@)` values, the stongest oxidizing agent is `[Fe(CN)_(6)]^(4-) rarr [Fe(CN)_(6)]^(3-)+e^(-), E^(@) = -0.35 V` `Fe^(2+) rarr Fe^(3+)+e^(-), E^(@) = -0.77 V`A. `[Fe(CN)_(6)]^(4-)`B. `Fe^(2+)`C. `Fe^(3+)`D. `[Fe(CN)_(6)]^(2-)` |
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Answer» Correct Answer - C Oxidizing agent oxidizes the other substance and gets reduced. Thus, higher the reduction potential, stronger the reducing agent: `[Fe(CN)_(6)]^(3-)+e^(-) rarr [Fe(CN)_(6)]^(4-),, E^(@) = 0.35 V` `Fe^(3+)+e^(-) rarr Fe^(2+),, E^(@) = 0.77 V` Since `E_(Fe^(3+)//Fe^(2+))^(@)gt E_([F^e(CN)_(6)]^(3-)//[Fe(CN)_(6)]^(4-)), Fe^(3+)` is the strongest oxidizing agent. |
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