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On the basisof the following thermochemical data ( Delta_(f)G_(H^(+))(aq)= 0) H_(2)O(l) rarrH^(+)(aq)+ OH^(-), DeltaH= 57.32kJ H_(2)(g) +(1)/(2) O_(2)(g) rarr H_(2)O(l) , DeltaH = -282.20 kJthe value of enthalpy of formation ofOH^(-) ion at25^(@)C is |
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Answer» `- 22.88 KJ ` `Delta_(R)H= [Delta_(f) H(H^(+))+Delta_(f)H^(@) ( OH^(-)) ]-Delta_(f)H^(@) (H_(2)O)` `:. 57.32 =0+ Delta_(f)H^(@) ( OH^(-)) - ( -286.2)` or `Delta_(f)H^(@) ( OH^(-)) =57.32 -286.2 = -228.88 kJ ` |
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