On the formation of SF_(6) by the direct combination of S and F_(2)which is the limiting reagent? Prove it.

On the formation of SF_(6) by the direct combination of S and F_(2)whi

1.	On the formation of SF_(6) by the direct combination of S and F_(2)which is the limiting reagent? Prove it.
Answer» Solution :`SF_(6)` is formed by burning Sulphur in an atmosphere of Fluorine. Suppose 3 MOLES of S is ALLOWED to react with 12 moles of Fluorine. `S_((l))+3F_(2_((g))) rarr SF_(6_((g)))` As per the stoichiometric reaction, one mole of S reacts with 3 moles of fluorine to COMPLETE the reaction. Similarly, 3 moles of S requires only 9 moles of fluorine. `:.` It is understood that the limiting REAGENT is Sulphur and the excess reagent is Fluorine.