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On the surface of earth, the escape velocity of a body is 11.2 km//s. If mass of earth is made half and radius becomes twice, then the escape velocity will become

Answer» <html><body><p>5.6 km/s<br/>22.<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> km/s<br/>33.4 km/s<br/>11.2 km/s</p>Solution :`V_(e)` = Initial escape velocity `= <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((2GM)/(R ))` <br/> `V_(e) = 11.2 km//s` <br/> `V_(e)` = Final escape velocity <br/> `= sqrt((2GM)/(2(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>))) = sqrt((<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(4)(2GM)/(R ))` <br/> `V._(e) = (1)/(2)V_(e)` <br/> = 5.6 km/s</body></html>


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