1.

On the surface of earth, the escape velocity of a body is 11.2 km//s. If mass of earth is made half and radius becomes twice, then the escape velocity will become

Answer»

5.6 km/s
22.4 km/s
33.4 km/s
11.2 km/s

Solution :`V_(e)` = Initial escape velocity `= SQRT((2GM)/(R ))`
`V_(e) = 11.2 km//s`
`V_(e)` = Final escape velocity
`= sqrt((2GM)/(2(2R))) = sqrt((1)/(4)(2GM)/(R ))`
`V._(e) = (1)/(2)V_(e)`
= 5.6 km/s


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