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On the surface of earth, the escape velocity of a body is 11.2 km//s. If mass of earth is made half and radius becomes twice, then the escape velocity will become |
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Answer» 5.6 km/s `V_(e) = 11.2 km//s` `V_(e)` = Final escape velocity `= sqrt((2GM)/(2(2R))) = sqrt((1)/(4)(2GM)/(R ))` `V._(e) = (1)/(2)V_(e)` = 5.6 km/s |
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