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On treating `PCl_(5)` with `H_(2)SO_(4)`, sulphuryl chloride `(SO_(2)Cl_(2))` is formed as the final product. This shows that `H_(2)SO_(4)`A. has two hydroxyl groups in its structureB. is a derivative of sulphur dioxideC. is a dibasic acidD. has greater affinity for water |
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Answer» Correct Answer - A `PCl_5+HO-underset(O)underset(||)overset(O)overset(||)S-OH toCl-underset(O)underset(||)overset(O)overset(||)S-Cl+POCl_(3)+H_(2)O` `PCl_(5)` attacks -OH group and replace it by -Cl group . Hence , reaction of `PCl_(5)` with `H_2SO_(4)` shows the presence of two -OH groups in `H_2SO_4` . |
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