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On which curve does the perpendicular tangents drawn to the hyperbola `(x^(2))/(25)-(y^(2))/(16)=1` intersect? |
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Answer» The locus of the point of intersection of prependicular tangents to `(x^(2))/(a^(2))-(y^(2))/(b^(2))=1` is the director circle given by `x^(2)+y^(2)=a^(2)-b^(2)` Hence, the perpendicular tangents drawn to `(x^(2))/(25)-(y^(2))/(16)=1` intersect on the curve `x^(2)+y^(2)=25-16=9` |
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