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One among the langthanides ,Ce(III), can be easily oxidized to Ce(IV)(At. No. of `Ce= 58)` . Explain why ? Or Of the lanthanides, cerium (At. No. 58) forms a tetrapositive ion, `Ce^94+)` in aqueous solution. Why? |
Answer» Ce(III) having the configuration `4f^(1) 5d^(-) 6s^(0)` can easily lose an electron to acquire the configuration `4f^(0)` and form Ce(IV) . In fact , this is the only `( + IV)` lanthanide which exists in solution. | |