One bisector of the angle between the lines given by `a(x-1)^(2)+2h(x-1)y+by^(2)=0` is `2x+y-2=0`. The equation of the other bisector isA. `x-2y+1=0`B. `x-2y-2=0`C. `x-2y-1=0`D. none of these

One bisector of the angle between the lines given by `a(x-1)^(2)+2h(x-

1.	One bisector of the angle between the lines given by `a(x-1)^(2)+2h(x-1)y+by^(2)=0` is `2x+y-2=0`. The equation of the other bisector isA. `x-2y+1=0`B. `x-2y-2=0`C. `x-2y-1=0`D. none of these
Answer» Correct Answer - C We have `a(x-1)^(2)+2h(x-1)(y-0)+b(y-0)^(2)=0` Clearly, it represents a pair of straight lines passing through (1, 0). Since the bisectors of the angles between two lines are always perpendicular. So, the other bisector passes through (1, 0) and is perpendicular to `2x+y-2=0`. Hence, is equation is `y-0=(1)/(2)(x-1)rArrx-2y-1=0`.

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