One box contains four cards numbered 1, 3, 5 and 7 and another box con

1.	One box contains four cards numbered 1, 3, 5 and 7 and another box contains four cards numbered as 2, 4, 6 and 8. One card is drawn from each box at random. The probability that the product of the numbers so drawn is more than 14 is: (1) 1 / 2 (2) 7 / 10 (3) 3 / 8 (4) 5 / 8
Answer» Correct option is (1) 1 / 2 Fav. cases = {(3 × 6), (3 × 8), (5 × 4), (5 × 6), (5 × 8), (7 × 4), (7 × 6), (7 × 8)} = 8 Total cases = 4 × 4 = 16 ∴ Probability Favorable / total = 8 / 16 = 1 / 2

One box contains four cards numbered 1, 3, 5 and 7 and another box contains four cards numbered as 2, 4, 6 and 8. One card is drawn from each box at random. The probability that the product of the numbers so drawn is more than 14 is: (1) 1 / 2 (2) 7 / 10 (3) 3 / 8 (4) 5 / 8

Answer»

Correct option is (1) 1 / 2

Fav. cases = {(3 × 6), (3 × 8), (5 × 4), (5 × 6), (5 × 8), (7 × 4), (7 × 6), (7 × 8)} = 8

Total cases = 4 × 4 = 16

∴ Probability Favorable / total = 8 / 16 = 1 / 2

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One box contains four cards numbered 1, 3, 5 and 7 and another box contains four cards numbered as 2, 4, 6 and 8. One card is drawn from each box at random. The probability that the product of the numbers so drawn is more than 14 is: (1) 1 / 2 (2) 7 / 10 (3) 3 / 8 (4) 5 / 8

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