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One branch of cos–1 other than the principal value branch corresponds to(A) [π/2, 3π/2](B) [π, 2π] - {3π/2}(C) (0, π)(D) [2π, 3π] |
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Answer» (D) is the correct answer. We know that the principal value branch of cos-1x is [0, π]. Also, we know that the period of cosθ is 2π. Now, let θ \(\in\) [2π, 3π] And cos(2π – θ) = cos θ Thus, 2π – θ \(\in\) [0, π]. Therefore, [2π, 3π] corresponds to the principal value branch for cos-1x. |
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