One cationic complex has to isomers `A` and `B` Each has one `Co^(3+)` five `NH_(3)` one `CI^(Θ)` and one `SO_(4)^(2-)` stoichiometically A give white precipitate with `BaCI_(2)` white `B` gives white precipitate with `AgNO_(3)` A can be .A. `[Co(NH_(3))_(5)]CISO_(4)`B. `[Co(NH_(3))_(5)SO_(4)]CI`C. `[Co(NH_(3))_(5)CI]SO_(4)`D. `[Co(NH_(3))_(4)SO_(4)]CI.NH_(3)`

One cationic complex has to isomers `A` and `B` Each has one `Co^(3+)`

1.	One cationic complex has to isomers `A` and `B` Each has one `Co^(3+)` five `NH_(3)` one `CI^(Θ)` and one `SO_(4)^(2-)` stoichiometically A give white precipitate with `BaCI_(2)` white `B` gives white precipitate with `AgNO_(3)` A can be .A. `[Co(NH_(3))_(5)]CISO_(4)`B. `[Co(NH_(3))_(5)SO_(4)]CI`C. `[Co(NH_(3))_(5)CI]SO_(4)`D. `[Co(NH_(3))_(4)SO_(4)]CI.NH_(3)`
Answer» Correct Answer - C A gives white ppt. with `BaCI(2)` so `SO_(4)^(2-)` ions is outside the complex entity as negative counter ion.Hence answer is© .

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