1.

One container having 0.4 g O_(2) and 0.06 g H_(2) at 100^(@)C then (a) What will be total pressure of container ?(b) This mixture of gas produce water at 100^(@)C temperature then which gas will left in container ? Calculate their partial pressure. (R = 6.0821 L atm mol^(-1)K^(-1))

Answer»

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ANSWER :`p_("total")=0.867` atm, `H_(2)` or `H_(2)O_((g))` It.s partial pressure are 0.102 atm and 0.51 atm RESPECTIVELY.


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