One day, during their vacation at beach resort, Shella found twice as

1.	One day, during their vacation at beach resort, Shella found twice as many sea shells as Anita and Anita found 5 shells more than sandy. Together sandy and Shella found 16 sea shells. How many did each of them find?
Answer» Let the number of sea shells found by sandy = x So, the number of sea shells found by Anita = (x + 5). The number of sea shells found by Shella = 2 (x + 5). According to the question, ⇒ x + 2(x + 5) = 16 ⇒ x + 2x +10 = 16 ⇒ 3x + 10 = 16 Subtracting 10 from both sides, we get ⇒ 3x + 10 – 10 = 16 – 10 ⇒ 3x = 6 Dividing both sides by 3, we get ⇒ 3x/6 = 6/3 ⇒ x = 4 Thus, the number of sea shells found by Sandy = x = 4, The number of sea shells found by Anita = x + 5 = 4 + 5 = 9, The number of sea shells found by Shelia = 2 (x + 5) = 2 (4 + 5) = 2(9) = 18.

One day, during their vacation at beach resort, Shella found twice as many sea shells as Anita and Anita found 5 shells more than sandy. Together sandy and Shella found 16 sea shells. How many did each of them find?

Answer»

Let the number of sea shells found by sandy = x

So, the number of sea shells found by Anita = (x + 5).

The number of sea shells found by Shella = 2 (x + 5).

According to the question,

⇒ x + 2(x + 5) = 16

⇒ x + 2x +10 = 16

⇒ 3x + 10 = 16

Subtracting 10 from both sides, we get

⇒ 3x + 10 – 10 = 16 – 10

⇒ 3x = 6

Dividing both sides by 3, we get

⇒ 3x/6 = 6/3

⇒ x = 4

Thus, the number of sea shells found by Sandy = x = 4,

The number of sea shells found by Anita = x + 5 = 4 + 5 = 9,

The number of sea shells found by Shelia = 2 (x + 5) = 2 (4 + 5) = 2(9) = 18.