One end of a long iron chain of linear mass density lambda is fixed to a sphere of mass m and specific density 1//3 while the other end is free. The sphere slong with the chain is immersed in a deep lake. If specific density or iron is 7, the height h above the bed of the lake at which the lake at which the sphere will float in equillibrium is (Assume that the part of the chain lying on the bottom of the lake exerts negligible force on the upper part of the chain.).

One end of a long iron chain of linear mass density lambda is fixed to

1.	One end of a long iron chain of linear mass density lambda is fixed to a sphere of mass m and specific density 1//3 while the other end is free. The sphere slong with the chain is immersed in a deep lake. If specific density or iron is 7, the height h above the bed of the lake at which the lake at which the sphere will float in equillibrium is (Assume that the part of the chain lying on the bottom of the lake exerts negligible force on the upper part of the chain.).
Answer» Solution :Weight of SPHERE `+` chain `= (m + lambdah)G` BUOYANT force `= (3m + (lambdah)/(7))g` for EQUILIBRIUM, weight `=` Buoyant force or, `m + lambdah = 3m + (lambdah)/(7)` or `h = (7m)/(3lambda)`