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One end of a string of length L is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:1. T.2. T –\(\frac{mv^2}{L}\)3. T + \(\frac{mv^2}{L}\)4. 0 T is the tension in the string. [Choose the correct alternative]. |
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Answer» 1. The centripetal force necessary for the particle to move in a circular path is provided by the tension in the string. Hence net force on the particle is nothing but tension T in the string. |
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