One end of the diameter of a circle is (1, 4). The center of the circl

1.	One end of the diameter of a circle is (1, 4). The center of the circle is (3, –4). Find the coordinates of other end
Answer» One end of the diameter = (x , y ) = (1, 4) Center of the circle = (x, y) =(3, -4) If other end of the diameter = (x₂, y₂) \(3=\frac{1+x_2}{2},\) ∴ x₂ = 6 - 1 = 5 - 4 = \(\frac{4+y_2}{2},\) ∴ y₂ = -8 - 4 = -12, Other end of the diameter (5 – 12)

One end of the diameter of a circle is (1, 4). The center of the circle is (3, –4). Find the coordinates of other end

Answer»

One end of the diameter = (x , y ) = (1, 4)

Center of the circle = (x, y) =(3, -4) If other end of the diameter = (x₂, y₂)

\(3=\frac{1+x_2}{2},\)

∴ x₂ = 6 - 1

= 5 - 4 = \(\frac{4+y_2}{2},\)

∴ y₂ = -8 - 4 = -12,

Other end of the diameter (5 – 12)

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One end of the diameter of a circle is (1, 4). The center of the circle is (3, –4). Find the coordinates of other end

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