One face of the a cube of side 0.2 m is in contact with ice and the opposite face is in contact with steam. If all other sides are well lagged, calculate the mass of ice that melts during one hour. Thermal conductivity of the metal =40 "Wm"^(-1) "K"^(-1). L.H. of fusion of ice =336 "kJ kg"^(-1).

One face of the a cube of side 0.2 m is in contact with ice and the op

1.	One face of the a cube of side 0.2 m is in contact with ice and the opposite face is in contact with steam. If all other sides are well lagged, calculate the mass of ice that melts during one hour. Thermal conductivity of the metal =40 "Wm"^(-1) "K"^(-1). L.H. of fusion of ice =336 "kJ kg"^(-1).
Answer» Solution :`m = KA ( theta_1 - theta_2) t// ANGLE X = 40 xx 0.04 xx 100 xx 3600//336 xx 10^(3)xx 0.2 = 8.571 "KG"`