One faraday of electricity is passed through molten `Al_(2)O_(3)`, aqueous solution of `CuSO_(4)` and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al, Cu and Na deposited at the respective cathodes isA. `2:3:6`B. `6:2:3`C. `6:3:2`D. `1:2:3`

One faraday of electricity is passed through molten `Al_(2)O_(3)`, aqu

1.	One faraday of electricity is passed through molten `Al_(2)O_(3)`, aqueous solution of `CuSO_(4)` and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al, Cu and Na deposited at the respective cathodes isA. `2:3:6`B. `6:2:3`C. `6:3:2`D. `1:2:3`
Answer» Correct Answer - A `Ag^(3+)+3e^(-)toAl` `Cu^(2+)+2e^(-)toCu` `Na^(+)+e^(-)toNa` thus 1F will be deposit `(1)/(3)` mole of `Al,(1)/(2)` mole of Cu and 1 mole of Na. Hence, molar ratio `=(1)/(3):(1)/(2):1=2:3:6`

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One faraday of electricity is passed through molten `Al_(2)O_(3)`, aqueous solution of `CuSO_(4)` and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al, Cu and Na deposited at the respective cathodes isA. `2:3:6`B. `6:2:3`C. `6:3:2`D. `1:2:3`

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