One fourth length of a spring of force constant k is cut away. The force constant of the remaining spring will be what ?

One fourth length of a spring of force constant k is cut away. The for

1.	One fourth length of a spring of force constant k is cut away. The force constant of the remaining spring will be what ?
Answer» `(3)/(4)k` `(4)/(3)k` `k` `4K` Solution :USING `k propto (1)/(l)` Here, one FOURTH length is cut, so the length of remaining PART is `(3)/(4)l` `therefore (k_2)/(k_1)= (l_1)/(l_2)= (l)/((3)/(4)l)= (4)/(3)` `therefore k_(2)= (4)/(3)k`.