1.

One gas having ratio of density is 1 : 2 and temperature ratio is 2 : 1 then what is ratio of pressure ?

Answer»

Solution :1 : 1
`d_(1)=(Mp_(1))/(RT_(1)) "" d_(2)=(Mp_(2))/(RT_(2))`
`THEREFORE p_(1)=(d_(1)RT_(1))/(M) p_(2)=(d_(2)RT_(2))/(M)`
`therefore (p_(1))/(p_(2))=(1xx R xx2)/(M)XX(M)/(2xx R xx1)=(1)/(1)`
(MOLAR mass M = constant, gas can.t change but state can change).


Discussion

No Comment Found