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One gas having ratio of density is 1 : 2 and temperature ratio is 2 : 1 then what is ratio of pressure ? |
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Answer» Solution :1 : 1 `d_(1)=(Mp_(1))/(RT_(1)) "" d_(2)=(Mp_(2))/(RT_(2))` `THEREFORE p_(1)=(d_(1)RT_(1))/(M) p_(2)=(d_(2)RT_(2))/(M)` `therefore (p_(1))/(p_(2))=(1xx R xx2)/(M)XX(M)/(2xx R xx1)=(1)/(1)` (MOLAR mass M = constant, gas can.t change but state can change). |
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