1.

One gm mole of an ideal gas at S.T.P is subjected to a reversible adiabatic expansion to double its volume. Find the change in internal energy in the process. Given gamma = 1. 4 [E.Q.]

Answer»

Solution :`T_(1) = 273 K, T _(2) = GAMMA = 1.4`
Final volume `V_(2) = 2 xx `Initial volume `V_(1)`
`(V _(2))/( V _(1)) = 2`
`T _(1) V _(1) ^( gamma -1) = T_(2) V _(2) ^( gamma -1)`
`T _(2) = ((V _(1))/( V _(2)) ) ^( gamma -1) xx T_(1) = ((1)/(2)) ^( 1. 4 -1 ) xx 273`
`= 20 7 K`
Changle in interanl energy `dU = (R )/(( gamma -1)) = (T_(1) -T_(2))`
`= (8. 31)/( ( 1. 4 -1)) ( 273 - 207)`
`= 1. 37 xx 10 ^(3) J`


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