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1. |
One kg of Calcium has how many g atom of aC2de |
Answer» <p>Given weight=1kg=1000g gram molecular weight of cacl2=40+71=111g no. of molecules=(given weight/gram molecular weight )*avagadro number avagadro number=6.023*10^23 No. of molecules=(1000/111)*6.023*10^23 =5.4*10^24 </p> | |