InterviewSolution
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InterviewSolution
| 1. |
d. A stone thrown vertically upwards withinitial velocity u reaches a height 'h'before coming down. Show that thetime taken to go up is same as the timetaken to come down. |
| Answer» <p>projected vertically upwards with initial velocity u which reaches a maximum height h.Acceleration due to gravity=-gEquation of Motion for a body projected thrown upwards :V=u-gt----------(1)h=ut-1/2gt² -----------(2)v²-u²=-2gh --------(3)</p><p>Equations of motion for freely falling body :for free fall :Initial velocity=u=0g=gV=gt----------(4)h=1/2gt²-------(5)v²=2gh------(6)Time of Ascent is the time taken by body thrown up to reach maximum height hAt maximum height , V=0</p><p>Equation (1) turns to u=gt1t1=u/g ----------(7)Maximm height h=u²/2g ----------(8)</p><p>Time of descent : After reaching maximum height , the body begins to travel downward like free fallso equation (5) h=1/2gt₂²t₂²=2h/gt₂=√2h/gbut from equation (9)t₂=√2xu²/2g²t₂=u/g -----------------equation (10)∴t₁=t₂The time ascent is equal to time of descent in case of bodies moving under gravity.</p> <p>projected vertically upwards with initial velocity u which reaches a maximum height h.Acceleration due to gravity=-gEquation of Motion for a body projected thrown upwards :V=u-gt----------(1)h=ut-1/2gt² -----------(2)v²-u²=-2gh --------(3)</p><p>Equations of motion for freely falling body :for free fall :Initial velocity=u=0g=gV=gt----------(4)h=1/2gt²-------(5)v²=2gh------(6)Time of Ascent is the time taken by body thrown up to reach maximum height hAt maximum height , V=0</p><p>Equation (1) turns to u=gt1t1=u/g ----------(7)Maximm height h=u²/2g ----------(8)</p><p>Time of descent : After reaching maximum height , the body begins to travel downward like free fallso equation (5) h=1/2gt₂²t₂²=2h/gt₂=√2h/gbut from equation (9)t₂=√2xu²/2g²t₂=u/g -----------------equation (10)∴t₁=t₂The time ascent is equal to time of descent in case of bodies moving under gravity.</p> | |