One lit of SO_(3)was placed in a two litre vessels of a certain temperature. The following equilibrium was established in the vessel 2SO_(3(g)) hArr2SO_(2(g)) +O_(2(g)) the equilibrium mixture reacted with 0.2 mole KMnO, in acidic medium. Kc value is 1.25 x10^(-x) then the value of x is:

One lit of SO_(3)was placed in a two litre vessels of a certain temper

1.	One lit of SO_(3)was placed in a two litre vessels of a certain temperature. The following equilibrium was established in the vessel 2SO_(3(g)) hArr2SO_(2(g)) +O_(2(g)) the equilibrium mixture reacted with 0.2 mole KMnO, in acidic medium. Kc value is 1.25 x10^(-x) then the value of x is:
Answer» Solution : Only `SO_(2)` is will oxidised So, no. of EQUIVALENT of `SO_(2)` = equivalent of `KMnO_(4)` `2x xx 2=0.2 xx 5 implies 2x=0.5` `Kc=(((0.5)/(2))^(2)((0.25)/(2)))/(((0.5)/(2))^(2))=0.125` `implies 1.25 xx 10^(-1)=1.25 xx 10^(-x) implies x=1`