InterviewSolution
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InterviewSolution
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One litre each of a Buffer solution is taken in two beakers connected through a salt bridge. Platinum electrode is immersed in each beaker and electrysis is carried out for `10,000` sec. using a current of `9.65` Ampere. The Buffer contain `(1)/(3)` mole each of `Na_(2)HPO_(4)` and `NaH_(2)PO_(4)` Initially. using the given data answer the following. Given: ltbr. `pK_(a) (H_(3)PO_(4)) = 4, pK_(a) (H_(2)PO_(4)^(-)) = 7 , pK_(a) (HPO_(4)^(2-)) = 10` `log 2 = 0.3, log3 = 0.48` `2.303 (RT)/(F) = 0.06 at 298K` After electrolysis if `H_(2)` gas is bubbled at 1 bar pressure on each platinum electrode, what is the `EMF` of resulting Galvenic cell.A. `1.09V`B. `0.29V`C. `0.59V`D. `0.39V` |
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Answer» Correct Answer - C `EMF = E_("cathode") - E_("Anode")` `E_(H^(+)//H_(2)) = E_(H^(+)//H_(2))^(@) -(0.0591)/(2)log.(1)/([H^(+)]^(2))` `E_(H^(+)//H_(2)) =- 0.059 pH` `EMF =- 0.0591 pH_("cathode") -(-0.0591 pH_("anode"))` `= (pH_("anode") -pH_("cathode")) 0.06` `= (11.91 -2.09) 0.06` `= 0.59` |
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