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One litre hard water contains 12.00 mg `Mg^(2+)` millieqivalent of washing soda required to remove its hardness isA. 1B. 12.6C. `1xx10^(-3)`D. `12.16xx10^(-3)` |
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Answer» Correct Answer - A `underset(1 g-eq)(Mg^(2+))+underset(1 g-eq)(Na_(2)CO_(3))toMgCO_(3)+2Na^(+)` 1 g- equivalent of `Mg^(2+)=12g of Mg^(2+)` =12000 mg of `Mg^(2+)` Now , 12000 mg of `Mg^(2+)-=1000` milleequivalent of `Na_(2)CO_(3)` `:.` 12 mg of `Mg^(2+)-=1` milliequivalent of `Na_(2)CO_(3)` |
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