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One litre of a gas weighs 2g at 300 K and 1 tm pressure. If the pressure is changed to 0.75 atm at which of the following temperatures, will one litre of the same gas weight 1 g? |
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Answer» Solution :According to ideal gas EQUATION, `PV = nRT = w//M RT` For a particular gas : `(P_(1)V_(1))/(P_(2)V_(2)) = (n_(1)RT_(1))/(n_(2)RT) = (w_(1)RT_(1))/(w_(2)RT_(2))` `(1 xx 1)/(0.75 xx 1) = (2 xx R xx 300)/(1 xx R xx T_(2))` or `T_(2) = 2 xx 300 xx 0.75 = 450 K` |
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