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One litre of a sample of hard water contains 1.62g of calcium hydrogen carbonte. What amount of lime is needed to remove hardness of `10^(6)` litres of such a sample |
Answer» `"Amount of" Ca(HCO_(3))_(2) "in" L=1.62g` `"Amount of" Ca(HCO_(3))_(2) "in" 10^(6)L= (1.62g)/(1L)xx(10^(6)L)=162xx10^(4)g` ` Ca(HCO_(3))_(2)+CaO+ to 2CaCO_(3)+H_(2)O` `162"g of" Ca(HCO_(3))_(2) "need lime"=56g` `162xx10^(4)"g of" Ca(HCO_(3))_(2) "need lime"=(56g)/(162g)xx(162xx10^(4)g)=(56g)/(162g)xx(162xx10^(4)g)` `" "=56xx10^(4)"g of CaO"=560kg ` |
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