1.

One litre of a sample of hard water contains 1.62g of calcium hydrogen carbonte. What amount of lime is needed to remove hardness of `10^(6)` litres of such a sample

Answer» `"Amount of" Ca(HCO_(3))_(2) "in" L=1.62g`
`"Amount of" Ca(HCO_(3))_(2) "in" 10^(6)L= (1.62g)/(1L)xx(10^(6)L)=162xx10^(4)g`
` Ca(HCO_(3))_(2)+CaO+ to 2CaCO_(3)+H_(2)O`
`162"g of" Ca(HCO_(3))_(2) "need lime"=56g`
`162xx10^(4)"g of" Ca(HCO_(3))_(2) "need lime"=(56g)/(162g)xx(162xx10^(4)g)=(56g)/(162g)xx(162xx10^(4)g)` `" "=56xx10^(4)"g of CaO"=560kg `


Discussion

No Comment Found

Related InterviewSolutions