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One litre of a solution of N/2 HCl was heated in beaker and it was observed that when the volume of solution got reduce to 600 mL, 3.25 g of HCl was lost. Calculate the normality of the resulting solution.A. 0.50 NB. 0.60 NC. 0.68 ND. 0.70 N |
Answer» Correct Answer - c 1 L of N/2 HCl contains `= (1)/(2)xx36.5 = 18.25 g` HCl now present `= 18.25 - 3.25 = 15 g` Now, volume = 600 mL = 0.600 L Normality `= (15)/(36.5)xx(1)/(0.600 L) = 0.685 N` |
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