One litre of hydrogen effused in 8min through a 8 fine aperture. What is the time required for the same volume of ozone to effuse under similar conditions?

One litre of hydrogen effused in 8min through a 8 fine aperture. What

1.	One litre of hydrogen effused in 8min through a 8 fine aperture. What is the time required for the same volume of ozone to effuse under similar conditions?
Answer» Solution :The ratio of times taken for same VOLUME of TWO gases, under similar conditions is given by Graham.s equation `(t_2)/(t_1) = SQRT((M_1)/(M_1)) " or " t_2 = t_1 sqrt((M_2)/(M_1))` Time required for OZONE to effuse `= 8 xx sqrt(48//2) = 39.2 `min.